A 2 kg block is suspended by a spring and for small vertical oscillations, time period is found to be 1 sec. Now another mass m is attached to the 2kg block and this time the new time period of oscillation is found to be 1.5 sec. Then the value of m (in kg) is

see full answer

Talk to JEE/NEET 2025 Toppers - Learn What Actually Works!

Real Strategies. Real People. Real Success Stories - Just 1 call away

An Intiative by Sri Chaitanya

answer is 1.

(Unlock A.I Detailed Solution for FREE)

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test

Detailed Solution

T1=2πMK and T2=2πm+MK∴T2T1=m+MM⇒m=MT2T12-1=294-1=2.5 kg

Watch 3-min video & get full concept clarity