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Q.

A 2 kg block is suspended by a spring and for small vertical oscillations, time period is found to be 1 sec. Now another mass m is attached to the 2kg block and this time the new time period of oscillation is found to be 1.5 sec. Then the value of m (in kg) is

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Detailed Solution

T1=2πMK and T2=2πm+MK∴T2T1=m+MM⇒m=MT2T12-1=294-1=2.5 kg

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