Questions
A 2 kg block of wood rests on a long table top. A 5 g bullet moving horizontally with a speed of is shot into the block and sticks to it. The block then slides 2.7 m along the table top and comes to a stop. The force of friction between the block and the table is
detailed solution
Correct option is A
Velocity of block just after collision, v=5×10-3×1502+5×10-3 (from conservation of linear momentum) = 0.374 ms-1Let F be the force of friction, then work done against friction = initial kinetic energyor F×2.7=12×2.005×(0.374)2⇒F=0.052 NTalk to our academic expert!
Similar Questions
A skier starts from rest at point A and slides down the hill without turning or breaking. The friction coefficient is . When he stops at point B, his horizontal displacement is s. What is the height difference between points A and B?
(The velocity of the skier is small, so that the additional pressure on the snow due to the curvature
can be neglected. Neglect also the friction of air and the dependence of on the velocity of the skier.)
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