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Questions  

A 500kg boat has an initial speed of  10ms1 as it passes under a bridge. At that instant a 50 kg man jumps straight down into the boat from the bridge. The speed of the boat after the man and boat attain a common speed is

a
10011ms−1
b
1011ms−1
c
5011ms−1
d
511ms−1

detailed solution

Correct option is A

V1=MVM+m=500×10500+50=500×10550=10011ms−1

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