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Q.

A 10kg body moves  along X-axis from x=0 to x=5m under the influence of a force given by F=5−2x+3x2. If  the body  starts from rest, the velocity at  x=5m is

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a

10ms−1

b

5ms−1

c

9ms−1

d

15ms−1

answer is B.

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Detailed Solution

W=KEf−KEi∫05 Fdx=12mv2−02∫05 5−2x+3x2dx=12×10v2−025[x]05−2x2205+3x3305=12×10×v225-25+125=12×10×v2125=5v2v=5ms−1
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