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Q.

A 20 kg body is pushed with a force of 7N for 1.5 sec then with a force of 5N for 1.7 sec and finally with a force of 10N for 3 sec, the total impulse applied to the body and change in velocity will be

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a

49Ns,12.5ms-1

b

49Ns, 2.45ms-1

c

98Ns, 4.9ms-1

d

4.9Ns,2.45ms-1

answer is B.

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Detailed Solution

J = F x t ,J = F1t1 + F2 t2 + F3 t3 , J = m(v - u)
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