First slide
Friction on inclined plane of angle more than angle of repose
Question

A 30 kg box has to move up an inclined plane of slope 30° to the horizontal with a uniform velocity of 5 ms-1.If the frictional force retarding the motion is 150N, the horizontal force required to move the box up is(g=10ms-2)

Moderate
Solution

Fcosθ=mgsinθ+f,f=μsN

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