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A 20 kg box has to move up an inclined slope of $30^{0}$ to the horizontal at a uniform velocity of $5 m s^{- 1}$ . If the frictional force retarding the motion is 150N, the horizontal force required to move up is ( $g = 10 m s^{- 2}$ )

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250×23N

300×32N

300N

150N

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detailed solution

Correct option is A

F=mgsinθ+f = 20×10×12×150=250 ; Fx=Fcosθ=250cos300=250×23

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A 20 kg box has to move up an inclined slope of 300 to the horizontal at a uniform velocity of 5ms−1 . If the frictional force retarding the motion is 150N, the horizontal force required to move up is (g=10ms−2 )

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Ready to Test Your Skills?

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A 20 kg box has to move up an inclined slope of $30^{0}$ to the horizontal at a uniform velocity of $5 m s^{- 1}$ . If the frictional force retarding the motion is 150N, the horizontal force required to move up is ( $g = 10 m s^{- 2}$ )