First slide

Second law

Question

A 10 kg boy standing in a 40 kg boat floating on water is 20 m away from the shore of the river. If the boy moves 8 m on the boat towards the shore, then how far is he from the shore? (Assume no friction between boat and water)

Moderate

A

12.0 m
B

13.6 m
C

12.8 m
D

11.6 m

Solution

Let the boat moves a distance x away from shore.
Then net displacement of boy towards shore = 8 - x
Now apply: $m_{1} x_{1} = m_{2} x_{2}$
$\Rightarrow 40 x = 10 (8 - x) \Rightarrow x = 1.6 m$
Distance of boy from shore = 20 - (8 - x) = 13.6 m

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