First slide

Power

Question

A 500-kg car, moving with a velocity of 36 kmh^-1 on a straight road unidirectionally, doubles its velocity in 1 min. The average power delivered by the engine for doubling the velocity is

Moderate

A

750 W
B

1050 W
C

1150 W
D

1250 W

Solution

$u = 10 {ms}^{- 1}, v = 20 {ms}^{- 1}$
Work done = Increase in kinetic energy
$= \frac{1}{2} \times 500 [20^{2} - 10^{2}] = \frac{500 \times 30 \times 10}{2}$
$Power = \frac{500 \times 30 \times 10}{2 \times 60} = 1250 W$

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