First slide

Power

Question

A 800 kg car moving with a velocity of 10 m/s along a straight road, doubles its velocity in 2 minutes. Then average power delivered by the engine in this interval is

Easy

A

1.5 KW
B

1 KW
C

0.5 KW
D

2.5 KW

Solution

Work done on the car by the engine
$W = \frac{1}{2} \times 800 (20^{2} - 10^{2}) Joule =12 \times 10^{4} J$
$∴$ Average power $= \frac{12 \times 10^{4}}{2 \times 60} W a t t = 1 K W$ .

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