A 900 kg elevator hangs by a steel cable for which the allowable stress is 1.15×108N/m2 . What is the minimum diameter required if the elevator accelerates upward at 1.5m/s2 . Take g= 10 m / s2

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6×10−25πm

6×10−210πm

3×10−210πm

3×10−25πm

answer is B.

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Detailed Solution

1.15×108=900(10+a)πd24⇒d=610πcm

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