First slide

Fluid statics

Question

A 50 kg girl wearing heel shoes balances on a single heel. The heel is circular with a diameter 1 cm. The pressure exerted by the heel on the horizontal floor is (Take g = 10 ${ms}^{- 2}$ )

Easy

A

$6.4 \times 10^{4} Pa$
B

${6.4 × 10}^{5} Pa$
C

$6.4 \times 10^{6} Pa$
D

$6.4 \times 10^{7} Pa$

Solution

Here, m = 50 kg, D = 1 cm = $10^{- 2} m, g = 10 {ms}^{- 1}$
$∴$ Pressure exerted by the heel on the horizontal floor is
$p = \frac{F}{A} = \frac{mg}{π {(\frac{D}{2})}^{2}} = \frac{4 mg}{{πD}^{2}}$
= $\frac{4 \times 50 kg \times 10 {ms}^{- 2}}{3.14 \times {(10^{- 2} m)}^{2}}$
= $6.4 \times 10^{6} Pa$

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