A $$100$$ kg gun fires a ball of $$1$$ kg horizontally from a cliff of height $$500$$ m. It falls on the ground at a distance of $$400$$ m from the bottom of the cliff. The recoil velocity of the gun is (Take$$ g $$=$$ $$10$$ $$ms-2)

Question

A $$100$$ kg gun fires a ball of $$1$$ kg horizontally from a cliff of height $$500$$ m. It falls on the ground at a distance of $$400$$ m from the bottom of the cliff. The recoil velocity of the gun is (Take$$ g $$=$$ $$10$$ $$ms-2)

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Here,Mass of the gun, M $$=$$ $$100$$ kgMass of the ball, m $$=$$ $$1$$ kgHeight of the cliff, h $$=$$ $$500$$ mg $$=$$ $$10$$ $$ms-2Time$$ taken by the ball to reach the ground ist $$=$$ $$2hg$$ $$=$$ $$2$$×$$50010$$ $$ms-2$$ $$=$$ $$10$$ sHorizontal distance covered $$=$$ $$ut400$$ $$=$$ u ×$$10According$$ to law of conservation of linear momentum, we $$get0$$ $$=$$ Mv $$+$$ muv $$=$$ $$-muM$$ $$=$$ $$-(1$$ $$kg)(40$$ $$ms-1)100$$ kg $$=$$ $$-0.4$$ $$ms-1-ve$$ sign shows that the $$direction-ve$$ sign shows that the direction of recoil of

A 100 kg gun fires a ball of 1 kg horizontally from a cliff of height 500 m. It falls on the ground at a distance of 400 m from the bottom of the cliff. The recoil velocity of the gun is (Take g = 10 ${ms}^{- 2}$ )

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A 100 kg gun fires a ball of 1 kg horizontally from a cliff of height 500 m. It falls on the ground at a distance of 400 m from the bottom of the cliff. The recoil velocity of the gun is (Take g = 10 ms-2)

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A 100 kg gun fires a ball of 1 kg horizontally from a cliff of height 500 m. It falls on the ground at a distance of 400 m from the bottom of the cliff. The recoil velocity of the gun is (Take g = 10 ${ms}^{- 2}$ )