Banner 0
Banner 1
Banner 2
Banner 3
Banner 4
Banner 5
Banner 6
Banner 7
Banner 8
Banner 9

Q.

A 30 kg load is suspended from the lower end of a wire 10 cm and 2 mm2 in cross sectional area. The upper half of the wire is iron and the lower half is copper. Find the elongation in the wire(Nearly) (Yiron=20×1010 N m−2, YCu=1.1×1011 N m−2)

see full answer

Your Exam Success, Personally Taken Care Of

1:1 expert mentors customize learning to your strength and weaknesses – so you score higher in school , IIT JEE and NEET entrance exams.
An Intiative by Sri Chaitanya

a

20×10−5m

b

15×10−5m

c

10×10−5m

d

5×10−5m

answer is C.

(Unlock A.I Detailed Solution for FREE)

Best Courses for You

JEE

JEE

NEET

NEET

Foundation JEE

Foundation JEE

Foundation NEET

Foundation NEET

CBSE

CBSE

Detailed Solution

Y=2Y1Y2Y1+Y2=220×1010 1.1×1011 20×1010 +1.1×1011 =14.66×1010  =15×1010Nm−2e=FLAy=30×10×10×10−22×10−6×15×1010=10×10−5m
Watch 3-min video & get full concept clarity
score_test_img

courses

No courses found

Get Expert Academic Guidance – Connect with a Counselor Today!

best study material, now at your finger tips!

  • promsvg

    live classes

  • promsvg

    progress tracking

  • promsvg

    24x7 mentored guidance

  • promsvg

    study plan analysis

download the app

gplay
mentor

Download the App

gplay
whats app icon
personalised 1:1 online tutoring