A $$30$$ kg load is suspended from the lower end of a wire $$10$$ cm and $$2$$ $$mm2$$ in cross sectional area. The upper half of the wire is iron and the lower half is copper. Find the elongation in the $$wire(Nearly)$$ (Yiron=20$$×$$1010$$ N m−$$2$$, $$YCu=1.1$$×$$1011$$ N m−$$2)

Question

A $$30$$ kg load is suspended from the lower end of a wire $$10$$ cm and $$2$$ $$mm2$$ in cross sectional area. The upper half of the wire is iron and the lower half is copper. Find the elongation in the $$wire(Nearly)$$ (Yiron=20$$×$$1010$$ N m−$$2$$, $$YCu=1.1$$×$$1011$$ N m−$$2)

Infinity Learn · Accepted Answer

$$Y=2Y1Y2Y1+Y2=220$$×$$1010$$ $$1.1$$×$$1011$$ $$20$$×$$1010$$ $$+1.1$$×$$1011$$ $$=14.66$$×$$1010$$  $$=15$$×$$1010Nm$$−$$2e=FLAy=30$$×$$10$$×$$10$$×$$10$$−$$22$$×$$10$$−$$6$$×$$15$$×$$1010=10$$×$$10$$−$$5m$$

A 30 kg load is suspended from the lower end of a wire 10 cm and $2 m m^{2}$ in cross sectional area. The upper half of the wire is iron and the lower half is copper. Find the elongation in the wire(Nearly) $(Y_{iron} = 20 \times 10^{10} N m^{- 2}, Y_{Cu} = 1.1 \times 10^{11} N m^{- 2})$

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A 30 kg load is suspended from the lower end of a wire 10 cm and 2 mm2 in cross sectional area. The upper half of the wire is iron and the lower half is copper. Find the elongation in the wire(Nearly) (Yiron=20×1010 N m−2, YCu=1.1×1011 N m−2)

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A 30 kg load is suspended from the lower end of a wire 10 cm and $2 m m^{2}$ in cross sectional area. The upper half of the wire is iron and the lower half is copper. Find the elongation in the wire(Nearly) $(Y_{iron} = 20 \times 10^{10} N m^{- 2}, Y_{Cu} = 1.1 \times 10^{11} N m^{- 2})$