A $$50kg$$ man is standing at one end of a $$25m$$ long boat. He starts running towards the other end. On reaching the other end his velocity is $$2ms$$–$$1relative$$ to the boat. If the mass of the boat is $$200$$ kg, final velocity of the boat is $$($$ in ms–$$1)$$, neglect friction between boat and water.

Question

A $$50kg$$ man is standing at one end of a $$25m$$ long boat. He starts running towards the other  end. On reaching the other end his velocity is $$2ms$$–$$1relative$$ to the boat. If the mass of the boat is $$200$$ kg, final velocity of the boat is $$($$ in ms–$$1)$$, neglect friction between boat and water.

Infinity Learn · Accepted Answer

m $$=$$ $$50kg$$; v $$=$$ $$2m/s$$. M $$=$$ $$200$$ kg;Let V $$=$$ Velocity of boat relative to the ground  and u $$=$$ velocity of man relative to the boat. Absolute velocity of man $$=$$ (V$$ $$-$$ $$u)Conserving$$ momentum, MV $$+$$ $$m(V$$ $$-$$ $$u) $$=$$ $$0$$

A 50kg man is standing at one end of a 25m long boat. He starts running towards the other end. On reaching the other end his velocity is 2ms^–1relative to the boat. If the mass of the boat is 200 kg, final velocity of the boat is ( in ms^–1), neglect friction between boat and water.

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A 50kg man is standing at one end of a 25m long boat. He starts running towards the other end. On reaching the other end his velocity is 2ms–1relative to the boat. If the mass of the boat is 200 kg, final velocity of the boat is ( in ms–1), neglect friction between boat and water.

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A 50kg man is standing at one end of a 25m long boat. He starts running towards the other end. On reaching the other end his velocity is 2ms^–1relative to the boat. If the mass of the boat is 200 kg, final velocity of the boat is ( in ms^–1), neglect friction between boat and water.