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Q.

A 50kg man is standing at one end of a 25m long boat. He starts running towards the other end. On reaching the other end his velocity is2ms−1 . If the mass of the boat is 200 kg, final velocity of the boat is ( inms−1 )

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a

25

b

23

c

85

d

83

answer is A.

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Detailed Solution

ACC_  to L.C.L.M m(Vm−Vb)=MVb mVm=(M+m)Vb Vb=mVmM+m=50×2250=25ms−1
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