An 80 kg man stands at the edge of a horizontal circular platform having a moment of inertia of 720 kgm-2 and a radius of 2 m. The platform is initially at rest and is free to rotate about a frictionless, vertical axel through its centre. The man then starts walking around the edge clockwise (as viewed from above) at a speed of 1.5 m/s relative to the earth then the work done by the man is

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90J

30 J

130 J

40J

answer is C.

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Detailed Solution

from conservation of angular momentum mvr + Iω =oω for the platform =mvrI=80×1.5×2720=13work done by the man is 12mv2+12Iω21280×94+72019=130

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