A $$15Kg$$ mass is accelerated from rest with a force of $$100N$$. As it moves faster, friction and air resistance create an oppositely directed retarding force given by $$FR=A+BV$$ . Where $$A=25$$ N and $$B=$$ $$0.5Nm/s$$ . At what velocity does the acceleration equal to one half of the initial acceleration ?

Question

A $$15Kg$$ mass is accelerated from rest with a force  of $$100N$$. As it moves faster, friction and air resistance create an oppositely  directed retarding force given by $$FR=A+BV$$     . Where  $$A=25$$ N and $$B=$$ $$0.5Nm/s$$     .  At what velocity  does the acceleration equal to one half of the initial acceleration  ?

Infinity Learn · Accepted Answer

$$FR=A+BV=25+0.5V$$       When $$u=0$$  F−$$FR=ma$$     $$100$$−$$25$$−$$0.5V0=15a$$     $$a=5ms$$−$$2$$      $$(initial$$  $$acceleration)F$$−$$FR=ma1$$       where $$a1=a2$$     $$100$$−$$25$$−$$0.5V=15$$×$$52$$     $$752=0.5V$$               $$V=75ms$$−$$1$$

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A 15Kg mass is accelerated from rest with a force of 100N. As it moves faster, friction and air resistance create an oppositely directed retarding force given by FR=A+BV . Where A=25 N and B= 0.5Nm/s . At what velocity does the acceleration equal to one half of the initial acceleration ?

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