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A 15Kg mass is accelerated from rest with a force of 100N. As it moves faster, friction and air resistance create an oppositely directed retarding force given by FR=A+BV . Where A=25 N and B= 0.5Nm/s . At what velocity does the acceleration equal to one half of the initial acceleration ?

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a

25ms−1

b

50ms−1

c

75ms−1

d

100ms−1

answer is B.

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Detailed Solution

FR=A+BV=25+0.5V When u=0 F−FR=ma 100−25−0.5V0=15a a=5ms−2 (initial acceleration)F−FR=ma1 where a1=a2 100−25−0.5V=15×52 752=0.5V V=75ms−1

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A 15Kg mass is accelerated from rest with a force of 100N. As it moves faster, friction and air resistance create an oppositely directed retarding force given by FR=A+BV . Where A=25 N and B= 0.5Nm/s . At what velocity does the acceleration equal to one half of the initial acceleration ?