First slide

Work

Question

A 10kg mass moves along x-axis. Its acceleration as a function of its position is shown in the figure. What is the total work done on the mass by the force as the mass moves from $x = 0$ to $x = 8 cm$

Moderate

A

$8 \times 10^{- 2} joules$
B

$16 \times 10^{- 2} joules$
C

$4 \times 10^{- 4} joules$
D

$1 .6 \times 10^{- 3} joules$

Solution

Work done = Area covered in between force displacement curve and displacement axis
= Mass $\times$ Area covered in between acceleration-displacement curve and displacement axis.
$= 10 \times \frac{1}{2} (8 \times 10^{- 2} \times 20 \times 10^{- 2})$
$= 8 \times 10^{- 2} J$

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