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Q.

A 10kg mass moves along x-axis. Its acceleration as a function of its position is shown in the figure. What is the total work done on the mass by the force as the mass moves from x=0 to x=8 cm

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a

8×10−2joules

b

16×10−2joules

c

4×10−4joules

d

1.6×10−3joules

answer is A.

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Detailed Solution

Work done = Area covered in between force displacement curve and displacement axis= Mass × Area covered in between acceleration-displacement curve and displacement axis.=10×12(8×10−2×20×10−2)=8×10−2 J
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