A $$1$$ kg mass is projected down a rough circular track (radius$$ $$=$$ $$2.0$$ $$m) placed in vertical plane as shown. The speed of the mass at point A is $$3$$ $$m/s$$ and at point B, it is $$6.0$$ $$m/s$$. How much work is done on the mass between A and B by the force of friction?

Question

Infinity Learn · Accepted Answer

Conservation of energy prinicipleKE at A $$=$$ $$12$$×$$1.0$$×$$3.02$$ $$=$$ $$4.5$$ JLoss in $$PE$$ between A and B $$=$$ $$1.0$$×$$10$$×$$2$$ $$=$$ $$20JGain$$ in $$KE$$ from A to B if there had been no friction $$=$$ $$20$$ JTotal $$KE$$ at B if there had been no friction $$=$$ $$4.5$$ $$+20$$ $$=$$ $$24.5$$ JBut actual $$KE$$ at B $$=$$ $$12$$×$$1.0$$×$$62$$ $$=$$ $$18$$ JLoss in energy duet to friction $$=$$ $$24.5$$ $$-18$$ $$=$$ $$6.5$$ J

A 1 kg mass is projected down a rough circular track (radius = 2.0 m) placed in vertical plane as shown. The speed of the mass at point A is 3 m/s and at point B, it is 6.0 m/s. How much work is done on the mass between A and B by the force of friction?

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