A $$1$$ kg mass is projected down a rough circular track (radius$$ $$=$$ $$2.0$$ $$m) placed in vertical plane as shown. The speed of the mass at point A is $$3$$ $$m/sand$$ at point B, it is $$6.0$$ $$m/s$$. How much work is done on the mass between A and B by the force of friction?

Question

Infinity Learn · Accepted Answer

Conservation of energy principleKE at A $$=$$ $$12$$×$$1.0$$×$$3.02$$ $$=$$ $$4.5$$ JLoss in $$PE$$ between A and B $$=1.0$$ x $$l0$$ x $$2$$ $$=$$ $$20JGain$$ in $$KE$$ from A to B if there had been no friction $$=$$ $$20JTotal$$ $$KE$$ at B if there had been no $$friction=$$ $$4.5$$ $$+$$ $$20$$ $$=$$ $$24.5$$ IBut actual $$KE$$ at B $$=$$ $$12$$×$$1.0$$×$$62$$ $$=$$ $$18$$ JLoss in energy due to friction $$=$$ $$24.5$$ $$-$$ $$l8$$ $$=$$ $$6.5$$ J

A 1 kg mass is projected down a rough circular track (radius = 2.0 m) placed in vertical plane as shown. The speed of the mass at point A is 3 m/s
and at point B, it is 6.0 m/s. How much work is done on the mass between A and B by the force of friction?

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A 1 kg mass is projected down a rough circular track (radius = 2.0 m) placed in vertical plane as shown. The speed of the mass at point A is 3 m/sand at point B, it is 6.0 m/s. How much work is done on the mass between A and B by the force of friction?

Remember concepts with our Masterclasses.

Ready to Test Your Skills?

free study material

A 1 kg mass is projected down a rough circular track (radius = 2.0 m) placed in vertical plane as shown. The speed of the mass at point A is 3 m/s
and at point B, it is 6.0 m/s. How much work is done on the mass between A and B by the force of friction?