Questions
A 60 kg mass is pushed with a enough force to start it moving and the same force is continued to act
afterwards. If the coefficient of static friction and sliding friction are 0.5 and 0.4 respectively, then the
acceleration of the body will be [BCECE (Mains) 2012]
detailed solution
Correct option is A
Kinetic friction force =μkR=μkmg=0.4×60×10=240 N and the limiting friction force=μsR=μsmg=0.5×60×10=300 NSo, the force applied on the body is 300 N and if the body is moving afterwards with the same force, then,Net accelerating force = Applied force - Kinetic forcem a=300-240⇒ a=60m=6060=1 ms-2Talk to our academic expert!
Similar Questions
Statement I : The familiar equation mg = R for a body on a table is true only if the body is in equilibrium.
Statement II : The equality of mg and R has no connection with the third law.
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