A 10 kg metal block is attached to a spring of spring constant 1000 Nm-1. A block is displaced from equilibrium position by 10 cm and released. The maximum acceleration of the block is

We know that in spring SHM, the restoring force is proportional to displacement,i.e.                              F=-mω2y                                        …(i)                                   F=-ky                                             …(ii)where, k = force constant of the spring.Given, m = 10 kg,   A = 10 cm = 0.1 m,  k = 1000 Nm-1Comparing both equations, we get          ω2=km⇒ω=km=100010⇒ω=10 rads-1and acceleration in SHM,         amax=-ω2·y=-102×(0.1)=-10 ms-2⇒amax=10 ms-2