Questions
0.014 kg of nitrogen is enclosed in a vessel at a temperature of 27 °C. Find the amount of heat energy to be supplied to the gas to double the rms speed of its molecules.
detailed solution
Correct option is C
The root mean square speed is related to absolute temperature T ascrms=3kTmFor a given gas, m is fixed. Therefore, crms∝T. Hence in order to double the root mean square speed, the absolute temperature must be increased to four times the initial value. Initial temperature T1=273+27=300K. Therefore, final temperature T2=4T1=1200K.Since the volume of the vessel is fixed, ∆V = 0. Hence the heat energy supplied to the gas does no work on the gas; it only increases the internal energy of the molecules.ΔU=nCvdT =mM×5R2×T2-T1 =0.014×10328×5×8.3142×1200-300 =9353JTalk to our academic expert!
Similar Questions
If four molecules of a gas have speed 2, 4, 6, 8 kms-1 respectively, then root mean square speed (in kms-1) will be .. and respectively.
799 666 8865
support@infinitylearn.com
6th Floor, NCC Building, Durgamma Cheruvu Road, Vittal Rao Nagar, HITEC City, Hyderabad, Telangana 500081.
JEE Mock Tests
JEE study guide
JEE Revision Notes
JEE Important Questions
JEE Sample Papers
JEE Previous Year's Papers
NEET previous year’s papers
NEET important questions
NEET sample papers
NEET revision notes
NEET study guide
NEET mock tests