Questions
A 5 kg rod of square cross section 5cm on a side and 1m long is pulled along a smooth horizontal surface by a force applied at one end. The rod has a constant acceleration of
detailed solution
Correct option is C
Let the force applied be p: thenP=ma=5×2=10NFor the element shown in the following figureT=ml(l−x)×a=51(1−x)×2=10(1−x)Elongation in dx is Δ(dx)dx=T/AYΔ(dx)=10(1−x)(5×10−2)2×15×109dxTotal elongationΔl=∫0110(1−x)25×10−4×15×109dx=0.4×10−6mTalk to our academic expert!
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