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A 40kg slab rests on a frictionless floor as shown in the figure. A 10kg block rests on the top of the slab. The static coefficient of friction between the block and slab is 0.60 , while the coefficient of kinetic friction is 0.40. The 10kg block is acted upon by a horizontal force 100N. If g=9.8ms−2, the resulting acceleration of the slab will be

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a

0.98 m/s2

b

1.47 m/s2

c

1.52 m/s2

d

6.1 m/s2

answer is A.

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Detailed Solution

Limiting friction between block and slab =μsmAg=0.6×10×9.8=58.8 NBut applied force on block A is 100 N.So the block will slip over the slab.Now kinetic friction works between block and slabFk=μkmAg=0.4×10×9.8=39.2 NThis kinetic friction helps to move the slab∴Accleration of slab=39.2 mB=39.240=0.98 m/s2

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A 40kg slab rests on a frictionless floor as shown in the figure. A 10kg block rests on the top of the slab. The static coefficient of friction between the block and slab is 0.60 , while the coefficient of kinetic friction is 0.40. The 10kg block is acted upon by a horizontal force 100N. If g=9.8ms−2, the resulting acceleration of the slab will be