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Q.

A 40 kg slab rests on a frictionless floor as shown in the figure. A l0 kg block rests on the top of the slab. The static coefficient of friction between the block and slab is 0.60 while the kinetic friction is 0.40. The l0 kg block is acted upon by a horizontal force 100 N. If g = 9.8 m/s2, the resulting acceleration of the slab will be

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a

1 m/s2

b

1.5 m/s2

c

2 m/s2

d

6 m/s2

answer is A.

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Detailed Solution

Limiting friction between block and slab - μsmAg = 0.6 x 10 x l0=60NBut applied force on block I is 100 N. So the block will slip over a slab.Now kinetic friction works between block and slabFK= μkmAg = 0.4 x l0 x l0 = 40 NThis kinetic friction helps to move the slabAcceleration of slab = 40mB = 4040 = 1 m/s2
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A 40 kg slab rests on a frictionless floor as shown in the figure. A l0 kg block rests on the top of the slab. The static coefficient of friction between the block and slab is 0.60 while the kinetic friction is 0.40. The l0 kg block is acted upon by a horizontal force 100 N. If g = 9.8 m/s2, the resulting acceleration of the slab will be