A $$40$$ kg slab rests on a frictionless floor as shown in the figure. A $$l0$$ kg block rests on the top of the slab. The static coefficient of friction between the block and slab is $$0.60$$ while the kinetic friction is $$0.40$$. The $$l0$$ kg block is acted upon by a horizontal force $$100$$ N. If g $$=$$ $$9.8$$ $$m/s2$$, the resulting acceleration of the slab will be

Question

A $$40$$ kg slab rests on a frictionless floor as shown in the figure. A $$l0$$ kg block rests on the top of the slab. The static coefficient of friction between the block and slab is $$0.60$$ while the kinetic friction is $$0.40$$. The $$l0$$ kg block is acted upon by a horizontal force $$100$$ N. If g $$=$$ $$9.8$$ $$m/s2$$, the resulting acceleration of the slab will be

Infinity Learn · Accepted Answer

Limiting friction between block and slab $$-$$ μsmAg $$=$$ $$0.6$$ x $$10$$ x $$l0=60NBut$$ applied force on block I is $$100$$ N. So the block will slip over a slab.Now kinetic friction works between block and $$slabFK=$$ μkmAg $$=$$ $$0.4$$ x $$l0$$ x $$l0$$ $$=$$ $$40$$ NThis kinetic friction helps to move the slabAcceleration of slab $$=$$ $$40mB$$ $$=$$ $$4040$$ $$=$$ $$1$$ $$m/s2$$

Remember concepts with our Masterclasses.

Ready to Test Your Skills?

free study material