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Q.

A 1 kg stone at the end of 1 m long string is whirled in a vertical circle at constant speed of 4 m/sec. The tension in the string is 6 N when the stone is at (g,= 10 m/sec2)

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a

top of the circle

b

bottom of the circle

c

half way down

d

none of the above

answer is A.

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Detailed Solution

Tension at the top =mv2r−mgTension at bottom =mv2r+mgTension in horizontal position =mv2rTension at top =mv2r−g=1(16−10)=6N
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