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A 1 kg stone at the end of 1 m long string is whirled in a vertical circle at constant speed of 4 m/sec. The tension in the string is 6 N when the stone is at (g,= 10 m/sec²)

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top of the circle

bottom of the circle

half way down

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detailed solution

Correct option is A

Tension at the top =mv2r−mgTension at bottom =mv2r+mgTension in horizontal position =mv2rTension at top =mv2r−g=1(16−10)=6N

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A 1 kg stone at the end of 1 m long string is whirled in a vertical circle at constant speed of 4 m/sec. The tension in the string is 6 N when the stone is at (g,= 10 m/sec2)

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A 1 kg stone at the end of 1 m long string is whirled in a vertical circle at constant speed of 4 m/sec. The tension in the string is 6 N when the stone is at (g,= 10 m/sec²)