First slide

Power

Question

A 1-kg stone at the end of 1 m long string is whirled in a vertical circle at a constant speed of 4 m $s^{- 1}$ . The tension in the string is 6 N when the stone is

Moderate

A

At the top of the circle
B

At the bottom of the circle
C

Half way down
D

None of above

Solution

$\frac{m v^{2}}{R} = \frac{1 \times 4^{2}}{1} = 16 N$
mg = 1 × 10 = 10 N
$T = m g c o s θ + \frac{m v^{2}}{R}$
6 = 10 cos $θ$ + 16 $\Rightarrow$ $θ$ = - 180°

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