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A 1-kg stone at the end of 1 m long string is whirled in a vertical circle at a constant speed of 4 m $s^{- 1}$ . The tension in the string is 6 N when the stone is

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At the top of the circle

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detailed solution

Correct option is A

mv2R=1×421=16 Nmg = 1 × 10 = 10 NT = mg cosθ+mv2R6 = 10 cos θ + 16⇒θ= - 180°

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A 1-kg stone at the end of 1 m long string is whirled in a vertical circle at a constant speed of 4 ms-1. The tension in the string is 6 N when the stone is

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A 1-kg stone at the end of 1 m long string is whirled in a vertical circle at a constant speed of 4 m $s^{- 1}$ . The tension in the string is 6 N when the stone is