A $$8$$ kg stone tied at the end of a string $$1$$ metre long is whirled in a vertical circle. At the instant when the string makes an angle θ with the vertical, the speed of the stone is $$4$$ $$ms-1$$ and the tension in the thread is $$104$$ N. Then θ is

Question

A $$8$$ kg stone tied at the end of a string $$1$$ metre long is whirled in a vertical circle. At the instant when the string makes an angle θ with the vertical, the speed of the stone is $$4$$ $$ms-1$$ and the tension in the thread is $$104$$ N. Then θ is

Infinity Learn · Accepted Answer

T $$-$$ mg $$cos$$θ $$=$$ $$mv2ror$$     $$104$$ $$-$$ $$8$$ × $$10$$ $$cos$$ θ $$=$$ $$8$$×$$4$$×$$42or$$ $$104-8$$ $$cos$$ θ $$=$$ $$64or$$ $$80$$ $$cos$$ θ $$=$$ $$104-$$ $$64or$$ $$cos$$θ $$=$$ $$4080$$ $$=$$ $$12$$θ $$=$$ $$600$$

A 8 kg stone tied at the end of a string 1 metre long is whirled in a vertical circle. At the instant when the string makes an angle $θ$ with the vertical, the speed of the stone is 4 $m s^{- 1}$ and the tension in the thread is 104 N. Then $θ$ is

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A 8 kg stone tied at the end of a string 1 metre long is whirled in a vertical circle. At the instant when the string makes an angle θ with the vertical, the speed of the stone is 4 ms-1 and the tension in the thread is 104 N. Then θ is

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A 8 kg stone tied at the end of a string 1 metre long is whirled in a vertical circle. At the instant when the string makes an angle $θ$ with the vertical, the speed of the stone is 4 $m s^{- 1}$ and the tension in the thread is 104 N. Then $θ$ is