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Q.

A 25 kg uniform solid sphere with a 20 cm radius is suspended by a vertical wire such that the point of suspension is vertically above the centre of the sphere. A torque of 0. l0 N-m is required to rotate the sphere through an angle of 1.0 rad and then maintain the orientation. If the sphere is then released, its time period of the oscillation will be:

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a

π second

b

2 π second

c

2π second

d

4π second

answer is .

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Detailed Solution

τ = -kθ0.1 = -k(1.0) where k is torsional constant of the wire.k = 110T = 2π25×25×(.2)2110 = 2π10×.2×.2×10 = 4π sec
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