A $$2$$ kg wooden block is suspended from fixed point by a light string of length $$1$$ m. A body of mass $$0.5$$ kg moving horizontally with velocity ‘V' strikes the block and sticks to it. After the impact the composite body swings in a vertical circle and comes to rest momentarily when the string is horizontal then V $$=$$

Question

Infinity Learn · Accepted Answer

It $$V1$$ be the velocity of the block just after impact, then conserving linear momentum,$$0.5$$×$$V=(2+0.5)V1$$⇒$$V1=V5$$ $$m/sconserving$$ energy, $$12$$×$$2.5$$×$$(V1)2=2.5$$×$$10$$×$$1$$⇒$$V1=20$$ $$m/s$$∴ $$V5=20$$⇒$$V=105$$ $$m/s$$

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