Questions
The kinetic energies of electron and proton are equal and is J. Then the relation between their de-Broglie wavelengths is
a
λp<λe
b
λp>λe
c
λp=λe
d
λp=2λe
detailed solution
Correct option is A
By using λ=h2mE,E=10-32 J=Constant for both particles. Hence λ∞1mSince mp>me So λp<λe.Talk to our academic expert!
Similar Questions
An electron is orbiting in 4th energy state in a hydrogen atom. The de-Broglie wavelength associated with this electron is nearly equal to
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