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Questions  

The kinetic energies for a planet in an elliptical orbit about the sun, at positions A, B and C are KA,KB and KC , respectively. AC is the major axis and SB is perpendicular to AC at the position of the sun S as shown in the figure. Then

a
KA < KB < KC
b
KA > KB > KC
c
KB > KA > KC
d
KB < KA < KC

detailed solution

Correct option is B

If r be the radial distance of a planet from the centre of sun , then conserving energy -1/2 mV2 + (-GMsm / r) = T.E.⇒ K = T.E + GMs m / rNow rA < rB < rC.: KA > KB > KC

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