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Q.

The kinetic energies for a planet in an elliptical orbit about the sun, at positions A, B and C are KA,KB and KC , respectively. AC is the major axis and SB is perpendicular to AC at the position of the sun S as shown in the figure. Then

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a

KA < KB < KC

b

KA > KB > KC

c

KB > KA > KC

d

KB < KA < KC

answer is B.

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Detailed Solution

If r be the radial distance of a planet from the centre of sun , then conserving energy -1/2 mV2 + (-GMsm / r) = T.E.⇒ K = T.E + GMs m / rNow rA < rB < rC.: KA > KB > KC
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