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The kinetic energy of an electron is 5 eV. Calculate the de-Broglie wavelength associated with it $(h = 6.6 \times 10^{- 34} Js, m_{e} = 9.1 \times 10^{- 31} kg)$

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5.47Ao

10.9 Ao

2.7 Ao

None of these

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detailed solution

Correct option is A

λ=h2mE=6.6×10-342×9.1×10-31×5×1.6×10-19=5.469×10-10m=5.47Ao

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The kinetic energy of an electron is 5 eV. Calculate the de-Broglie wavelength associated with it (h=6.6×10-34Js,me=9.1×10-31kg)

Remember concepts with our Masterclasses.

Ready to Test Your Skills?

free study material

The kinetic energy of an electron is 5 eV. Calculate the de-Broglie wavelength associated with it $(h = 6.6 \times 10^{- 34} Js, m_{e} = 9.1 \times 10^{- 31} kg)$