The kinetic energy K of a particle moving along a circle of radius R depends upon the distance s as K = as2. The force acting on the particle is

Given that K=as2 or 12mv2=as2or mv2=2as2   ………..(i)Differentiating w.r.t. time, we getm(2v)×dvdt=2a×2s×dsdt But dsdt=vSo 2mdvdt=4as or mdvdt=2asNow, mdvdt= tangential force =FtFt=2as Centripetal force Fr=mv2R=2as2RFnet=Ft2+Fr2=(2as)2+2as2R2=2as1+s2R2