The kinetic energy of a man is half of that of a boy whose mass is half of that of man. When the man speeds up by 5ms-1, his kinetic energy is 100% more than that of the boy. The initial velocity of man is

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2(2−1)ms−1

2(2+1)ms−1

2ms-1

5ms-1

answer is D.

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Detailed Solution

KEman =12KEboy12m1v12=12m2v22m1v12=12×m12×v22v2=2v1→1KEman =2KEb12m1v1+52=2×12m12v22v1+5=2v1v1=5ms−1

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