Question

Kinetic energy of a particle is increased by $50 %$ without change in its mass. Find the percentage change in its momentum.

Moderate

Solution

$p = \sqrt{2 K m} K^{'} = 1.5 K p^{'} = \sqrt{2 K^{'} m} = \sqrt{2 (1.5 K) m}$
From eqs. (i) and (ii), we get
$p' = 1.22 p$
Therefore, percentage change in momentum is approximately $22%.$

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