Q.

Kinetic energy of a particle of mass 40 gm executing simple harmonic motion along a straight line is given by K=161−0.25x2  joule where x is in cm. Then frequency of oscillation of the particle is

see full answer

High-Paying Jobs That Even AI Can’t Replace — Through JEE/NEET

🎯 Hear from the experts why preparing for JEE/NEET today sets you up for future-proof, high-income careers tomorrow.
An Intiative by Sri Chaitanya

a

5002πHz

b

500πHz

c

250πHz

d

1000πHz

answer is A.

(Unlock A.I Detailed Solution for FREE)

Detailed Solution

Kinetic energy K=12mω2A21−x2A2Comparing this equation with the given equation we get, A2=10.25⇒A=2 cmand 12mω2A2=16⇒12×401000.ω2.21002=16⇒ω2=16×50×2500 ω=10002 rad/s∴ f=ω2π=5002π Hz
Watch 3-min video & get full concept clarity
Related Blogs
Get ₹ 1 crore* worth scholarship for JEE / NEET / Foundation
Result Producing online coaching for JEE/NEET of south India
Largest All India Test Series for JEE/NEET
Best Online Course for IIT JEE
Best Online Course for NEET
Best Online Course for CBSE
score_test_img

Get Expert Academic Guidance – Connect with a Counselor Today!

Related Blogs
Get ₹ 1 crore* worth scholarship for JEE / NEET / Foundation
Result Producing online coaching for JEE/NEET of south India
Largest All India Test Series for JEE/NEET
Best Online Course for IIT JEE
Best Online Course for NEET
Best Online Course for CBSE
whats app icon