The kinetic energy of a particle is SHM is 4 J when it passes through the mean position. If its mass is 2 kg and amplitude is 1 m, its time period is

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π2sec

π sec

2π sec

4π sec

answer is B.

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Detailed Solution

KE=12mω2A2⇒4=12×2×4π2T2×1⇒T=πsec

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