The kinetic energy and the potential energy of a particle executing SHM are equal. The ratio of its displacement and amplitude willl be

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answer is A.

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Detailed Solution

Given KE = PE ⇒ 12mv2 = 12kx2⇒ 12mω2(a2-x2) = 12mω2x2 ⇒ a2-x2 = x2 ⇒ x2 = a22⇒ xa = 12

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