Questions
The kinetic energy and potential energy of a particle executing simple harmonic motion will be equal, when displacement (amplitude = a) is
a
a2
b
a2
c
a2
d
a23
detailed solution
Correct option is C
Suppose at displacement y from mean position potential energy = kinetic energy ⇒12m(a2−y2)ω2=12mω2y2⇒a2=2y2 ⇒y=a2Talk to our academic expert!
Similar Questions
When the displacement is half the amplitude, the ratio of potential energy to the total energy is
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