Q.

The kinetic energy and potential energy of a particle executing simple harmonic motion will be equal, when displacement  (amplitude = a) is

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a

a2

b

a2

c

a2

d

a23

answer is C.

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Detailed Solution

Suppose at displacement y from mean position potential energy = kinetic energy ⇒12m(a2−y2)ω2=12mω2y2⇒a2=2y2 ⇒y=a2
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