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Questions  

In kinetic theory of gases, a molecules of mass ‘m’ of an ideal gas, collide with a wall of vessel with velocity ‘v’. The change in the linear momentum of the molecule is 

a
2 mv
b
mv
c
-mv
d
zero

detailed solution

Correct option is A

Δp→=pfinal−p¯lnitial  ;Δp→=change in momentum;   pfinal=final momentum;p¯lnitial=initial momentum;m=mass;v=velocity ΔP→=P¯f−P¯l=m(−v)−mv=−2mv if initial velocity=v; fina velocity =-v; negative  since opposite in direction to v |ΔP|=2mv

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Similar Questions

N molecules, each of mass m of gas A, and 2N molecules, each of mass 2m of gas  B, are contained in the same vessel which is maintained at a temperature T. The  mean square of the velocity of the molecules of B type is denoted by vB2  and the  mean square of the x-component of the velocity of A type is denoted by vA2 . The  ratio  vB2vA2=N3 . Find N.


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