In LC circuit the inductance L=40 mH and capacitance C=100 μF . If a voltage Vt=10sin314 t is applied to the circuit, the current in the circuit is given as

XL=wL =314×40×10−3=12560×10−3 =12.56Ω​XC=1wc=1314×100×10−6  =1000314 =31.84ΩPhaser diagramVmax=imaxXC−XL      ​⇒10=imax31.84−12.56​⇒imax=1019.28=0.52         ​ Since, XC>XL Current leads the voltage by   π 2 i=imaxsinwt+π2=0.52sin314t+π2=0.52cos314t