Questions
In circuit the inductance and capacitance . If a voltage is applied to the circuit, the current in the circuit is given as
a
5.2cos314 t
b
0.52cos314t
c
10cos314t
d
0.52sin314 t
detailed solution
Correct option is B
XL=wL =314×40×10−3=12560×10−3 =12.56ΩXC=1wc=1314×100×10−6 =1000314 =31.84ΩPhaser diagramVmax=imaxXC−XL ⇒10=imax31.84−12.56⇒imax=1019.28=0.52 Since, XC>XL Current leads the voltage by π 2 i=imaxsinwt+π2=0.52sin314t+π2=0.52cos314tTalk to our academic expert!
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