First slide

Work done by Diff type of forces

Question

A ladder 'AB' of weight 300N and length 5m is lying on a horizontal surface. Its centre of gravity is at a distance of '2m' from end A. A weight of 80N is attached at end B. The work done in raising the ladder to the vertical position with end 'A' in contact with the ground is,

Easy

A

500J
B

1000J
C

1150J
D

1900J

Solution

W = mgh + Mg $h_{c m}$ = (80 x 5 + 300 x 2) J
W = 400 + 600 = 1000 J

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