A ladder 2.5 m long and 150 N weight has its center of gravity 1 m from one end. At the other end 40 N load is attached. The whole system is horizontal. The work to be done to keep the ladder in vertical position so that the load is at the top end is ………joule

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250

500

750

400

answer is A.

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Detailed Solution

w =m2gh2 + m1gh1 =150 x 1+ 40 x 2.5 =250 joule

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