First slide

Work done by Diff type of forces

Question

A ladder 2.5 m long and 150 N weight has its center of gravity 1 m from one end. At the other end 40 N load is attached. The whole system is horizontal. The work to be done to keep the ladder in vertical position so that the load is at the top end is ………joule

Difficult

A

250
B

500
C

750
D

400

Solution

w =m₂gh₂ $+$ m₁gh₁ $= 150 x 1 + 40 x 2.5 = 250 j o u l e$

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