Questions
A ladder of mass 10kg is lying on horizontal surface. A body of weight 200N is attached to one end of ladder. If length is 5m and its centre of mass is at a distance of 2m from one end, the total work done in lifting the ladder to vertical position is
detailed solution
Correct option is D
W=Wload+WbodyW=mlghl+mbghbW=[10×10×2]+[200×5]W=200+1000⇒W=1200JTalk to our academic expert!
Similar Questions
If W1, W2 and W3 represent the work done in moving a particle from A to B along three different paths 1, 2 and 3 respectively (as shown) in the gravitational field of a point mass m, find the correct relation between W1, W2 and W3
799 666 8865
support@infinitylearn.com
6th Floor, NCC Building, Durgamma Cheruvu Road, Vittal Rao Nagar, HITEC City, Hyderabad, Telangana 500081.
JEE Mock Tests
JEE study guide
JEE Revision Notes
JEE Important Questions
JEE Sample Papers
JEE Previous Year's Papers
NEET previous year’s papers
NEET important questions
NEET sample papers
NEET revision notes
NEET study guide
NEET mock tests