A lamp emits monochromatic green light uniformly in all directions. The lamp is 3% efficient in converting electrical power to electromagnetic waves and consumes 100 W of power. The amplitude of the electric field associated with the electromagnetic radiation at a distance of 5m from the lamp will be nearly.

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1.34 V/m

2.68 V/m

4.02 V/m

5.36 V/m

answer is B.

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Detailed Solution

Wavelength of monochromatic green light=5.5×10−5cm IntensityI=PowerArea=100×(3100)4π(5)2=3100πWm−2 Now, half of this intensity (I) belongs to electric field and half of that to magnetic field, therefore, I2=14ε0E02C or E0=2Iε0C=2×(3100π)(14π×9×109)×(3×108)=625×30=7.2 ∴E0=2.68V/m

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