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Q.

A lamp emits monochromatic light uniformly in all directions. The lamp is 3% efficient in converting electrical power to electromagnetic waves and consumes 100 W of electrical power. The amplitude of the electric field associated with the electromagnetic radiation at a distance of 10m from the lamp will be

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a

9.37Vm−1

b

5.36Vm−1

c

2.68Vm−1

d

1.34Vm−1

answer is D.

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Detailed Solution

Useful intensity,  I=powerareaI=100×(3/100)4π(10)2=34π×100Wm−2 Half of this intensity (I) belongs to electric field and half of that to magnetic field . Therefore, I2=14∈0E02C   ⇒E0=2I∈0C⇒E0=2×34π×10014π×9×109×3×108E0=2×3×4π×9×1094π×100×3×108=2×910=35=1.34Vm−1
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