The lamp of flash light is 1 .5 Ω. It uses 3 cells each of 1 . 5 V and internal resistance 0 . 25 Ω. What is the net potential difference across the lamp ?

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1.5 V

2.25 V

3 V

4.5 V

answer is C.

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Detailed Solution

3E=(1⋅5+3r)ior 3×1⋅5=(1⋅5+0⋅75)ii = 2amp∴ Potential difference = 2 x 1.5= 3 V

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